import org.springframework.context.support.ClassPathXmlApplicationContext;

/**
 * @Auther: zhaozeyang
 * @Date: 2018/9/2 18:09
 * @Description:
 */
public class Start {

    public static void main(String[] args) {
        ClassPathXmlApplicationContext context=new ClassPathXmlApplicationContext(new String[]{"application.xml"});

        context.start();
        System.out.println("Provider started.");
    }


}
